Math Is Easy - Use Algebra To Solve Word Problem 7!Find four consecutive integers whose sume is -118. (Note1)Since consecutive integers differ by 1 (1,2,3), we canrepresent them as follows:let n represent the smallest of the four consecutiveintegers; then n + 1 represents the second largest, n + 2 represents the third largest, and n + 3 representsthe largest .We can now create the following equation: n + (n + 1) + (n + 2) + (n + 3) = -118Solve this equationn + (n + 1) + (n + 2) + (n + 3) = -118n + n + 1 + n +2 + n + 3 = -118Remove parentheses4n + 6 = -118Add the common terms4n + 6 = -118 - 6 = -6 Subtract 6 from each side4n + 0 = -1244n= -1244n/4= -124/4 Divide each side by 4 n =-31Now we substitute the answerfor n into the original equation to see if it works.n + (n + 1) + (n + 2) + (n + 3) =-118-31 + (-31 + 1) + (-31 + 2)(-31 + 3) = -118-31 + -30 + -29 + -28 = -118-118 = -118We must also see if the solution works in theoriginal problem statement.Find four consecutive integers whose sume is 118.Find four consecutive integers (-31, -30, -29,-28 are consecutive integers) whose sume is -118.Find four consecutive integers (-31 + -30 + -29 + -28 = -118) whose sume is -118.-118 = -118We have just solved a first degree equation.(Note1)The source for the problem statement is:Intermediate AlgebraFor College Students by Jerome E. Kaufman CloseWindow